css - 如何在切換IMg2 img3 img4的時候第一張圖片消失
問題描述
<!DOCTYPE html><html ><head> <title> new document </title> <meta charset='utf-8' /> <style> #pic{width:350px;height:350px;border:1px solid #ddd;margin-top:20px; } #link a{diaplay:inline-block;border:1px solid #ddd;background-color:gray;padding:5px 10px; } #pic a img:not([class=’pic1’]){display:none; } #pic a:target img{display:block; } </style></head><body> <p id=’link’><a href=’#img1’>img1</a><a href=’#img2’>img2</a><a href=’#img3’>img3</a><a href=’#img4’>img4</a> </p> <p id=’pic’><a name=’img1’><img src=’images/p001.jpg’ class=’pic1’ /></a><a name=’img2’><img src=’images/p002.jpg’ class=’pic2’ /></a><a name=’img3’><img src=’images/p003.jpg’ class=’pic3’ /></a><a name=’img4’><img src=’images/p004.jpg’ class=’pic3’ /></a> </p></body></html>
問題解答
回答1：用jquery的$(’#img1’).css(’display’,’none’);
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